How are partitions of unity used to construct a Riemannian metric on any smooth manifold?
Think about your answer, then reveal below.
Model answer: In each coordinate chart (Uα, φα), the standard Euclidean inner product on ℝⁿ pulls back to a Riemannian metric gα on Uα. Using a partition of unity {ρα} subordinate to {Uα}, define g = Σα ρα · gα. This sum is well-defined (locally finite), smooth, and at each point is a convex combination of inner products — hence positive definite. The result is a globally defined Riemannian metric. This construction shows that every smooth manifold admits a Riemannian metric.
The key insight is that the set of inner products on a vector space is convex — a positive combination of inner products is again an inner product. Since partition-of-unity functions are non-negative and sum to 1, the combination g = Σ ρα gα is a convex combination at each point, hence positive definite. This convexity argument works for metrics but fails for other structures (like symplectic forms) where the 'space of structures' is not convex.