Questions: Pipe System Analysis: Major and Minor Losses
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
A pipe system has a long straight run of pipe and a single partially-closed gate valve (K = 50). An engineer dismisses the valve as a 'minor loss.' What does the analysis actually show?
AThe engineer is correct — minor losses are by definition smaller than major losses
BThe valve loss could easily exceed the friction loss in the straight pipe, despite the 'minor' label
CThe valve loss is negligible because K is unitless
DMinor losses only matter when the pipe diameter is very small
The term 'minor loss' is a misnomer inherited from long-pipeline design where friction dominates. In short piping systems with fittings, minor losses frequently dominate. A partially-closed gate valve with K = 50 contributes h_m = 50·V²/2g, which can easily exceed the Darcy-Weisbach friction loss h_f = f(L/D)(V²/2g) if L/D is not very large. The name refers to the category, not the magnitude.
Question 2 Multiple Choice
Two pipes (A and B) connect the same two reservoirs in parallel. Pipe A has twice the head loss of Pipe B at any given flow rate. How does the flow distribute between the branches?
AEqual flow in both, since they connect the same two points
BAll flow goes through Pipe B, since it has less resistance
CFlow splits so that both branches have the same head loss, with more flow in B
DTotal head loss equals the sum of head losses in A and B
In a parallel pipe network, both branches connect the same two pressure nodes, so the head loss across each branch must be equal — this is a constraint imposed by the network topology, not something that can be avoided. The flow distribution self-adjusts so that this pressure compatibility is satisfied, with more flow going to the lower-resistance branch. Option D describes series networks, not parallel ones; in parallel, the total flow is the sum of branch flows, but the head loss is the same for each branch.
Question 3 True / False
'Minor losses' from pipe fittings are generally smaller in magnitude than 'major losses' from pipe wall friction.
TTrue
FFalse
Answer: False
The name 'minor losses' is misleading. In short piping systems with multiple fittings, valves, and bends, the sum of minor losses can far exceed the friction (major) loss. A partially-closed globe valve can have K > 300. The distinction is categorical (type of source: friction vs. local disturbance), not a statement about relative magnitude. Always compute both and compare.
Question 4 True / False
In a system of pipes connected in parallel, the total head loss from inlet to outlet is the same as the head loss through any single branch.
TTrue
FFalse
Answer: True
This is the fundamental constraint of parallel pipe networks: all branches connect the same two pressure nodes, so the head loss from one node to the other must be identical for each path. What differs between branches is the flow rate — each carries different flow based on its resistance. The system distributes total flow among branches so that this pressure-compatibility condition is exactly satisfied.
Question 5 Short Answer
Why does halving the diameter of a pipe have such a dramatic effect on the major head loss, even if the flow rate stays the same?
Think about your answer, then reveal below.
Model answer: Halving the diameter quadruples the velocity (by continuity: Q = AV, so V = Q/A, and A ∝ D², so V ∝ 1/D²). The Darcy-Weisbach equation shows h_f = f(L/D)(V²/2g). The velocity head V²/2g scales as 1/D⁴, and the L/D term scales as 1/D, giving an overall scaling of h_f ∝ 1/D⁵ for constant flow rate. Halving the diameter increases major head loss by a factor of 32.
The key is that velocity appears squared in the head loss formula, and velocity itself scales inversely with the square of diameter from continuity. So diameter affects head loss through two amplifying pathways simultaneously: the velocity head term (V²/2g) and the L/D geometric ratio. This is why small pipes in distribution networks require very careful sizing — small reductions in diameter cause large increases in pressure drop and required pump energy.