Questions: Polarography

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A polarographic experiment measures Cd²⁺ in 1 M KCl, finding E₁/₂ = −0.40 V. The supporting electrolyte is then changed to 0.1 M HNO₃. What should the experimenter expect?

AE₁/₂ remains at −0.40 V because it is a fixed property of cadmium
BE₁/₂ shifts because the half-wave potential depends on the analyte–electrolyte system, not the analyte alone
CE₁/₂ disappears entirely because cadmium cannot be reduced in nitric acid
DThe diffusion current changes but E₁/₂ stays constant
Question 2 Multiple Choice

In a DC polarogram, why does the current plateau at the limiting diffusion current (id) rather than continuing to rise as potential becomes more negative?

AThe electrode becomes fully coated with reduced metal, blocking further reaction
BEvery analyte molecule arriving at the electrode surface is immediately reduced, so the rate is set by diffusion, not electrode kinetics
CThe mercury drop falls off before higher currents can develop
DCapacitive charging current cancels the faradaic current at very negative potentials
Question 3 True / False

The primary analytical advantage of the dropping mercury electrode is that each new drop provides a fresh, uncontaminated surface, eliminating memory effects from previous measurements.

TTrue
FFalse
Question 4 True / False

The half-wave potential measured for cadmium in 1 M KCl is an intrinsic property of cadmium ions and remains the same regardless of the supporting electrolyte used.

TTrue
FFalse
Question 5 Short Answer

Why does mercury provide a wider cathodic potential window than solid platinum or carbon electrodes?

Think about your answer, then reveal below.