Questions: Principal, Angular, and Magnetic Quantum Numbers in Atoms

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Two electrons both have n=2 and ℓ=1, but one has m_ℓ = +1 and the other has m_ℓ = 0. In a hydrogen atom with no applied magnetic field, which electron has higher energy?

Am_ℓ = +1 has higher energy because its z-component of angular momentum is larger
Bm_ℓ = 0 has higher energy because it corresponds to the 'central' orbital orientation
CThey have the same energy — without an applied field, all m_ℓ states with the same n and ℓ are degenerate
DEnergy depends on m_ℓ but the calculation requires knowing the spin quantum number too
Question 2 Multiple Choice

What is the magnitude of the orbital angular momentum for an electron with ℓ = 2?

A2ℏ
B4ℏ
Cℏ√6
Dℏ√4 = 2ℏ (same as answer A)
Question 3 True / False

For an electron with ℓ = 1 and m_ℓ = 1, the total orbital angular momentum magnitude is ℏ, since L_z = m_ℓ·ℏ = ℏ implies the full angular momentum is ℏ.

TTrue
FFalse
Question 4 True / False

In a hydrogen atom with no applied magnetic field, an electron in the 2p subshell (n=2, ℓ=1) exists in one of three distinct energy levels corresponding to m_ℓ = −1, 0, +1.

TTrue
FFalse
Question 5 Short Answer

Why can we simultaneously know |L|² (the squared magnitude of orbital angular momentum) and L_z (one component), but not all three components L_x, L_y, L_z simultaneously? What physical principle prevents this?

Think about your answer, then reveal below.