Questions: Reflective and Coreflective Subcategories

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A student says: 'The category Ab of abelian groups is reflective inside Grp because we can quotient any group G by its commutator subgroup [G,G] to get an abelian group. That's the whole story.' What crucial fact is missing from this description?

AThe construction is wrong — the reflection is the center Z(G), not the commutator quotient
BThe construction is not functorial and cannot be applied consistently to group homomorphisms
CThe reflection G → G/[G,G] has a universal property: every group homomorphism from G to any abelian group factors uniquely through it — this is what makes it the *reflector*, not just any quotient
DAb is not reflective in Grp; it is coreflective because the inclusion has a right adjoint
Question 2 Multiple Choice

Which of the following correctly characterizes the reflector L: C → D in a reflective subcategory D ⊆ C?

AL is a functor that sends each object of C to an arbitrarily chosen object of D
BFor each object X in C, L(X) is the object of D such that any morphism from X to any object A in D factors uniquely through the unit map η_X: X → L(X) in C
CL is the right adjoint of the inclusion functor i: D ↪ C
DL is surjective on objects: every object of D appears as L(X) for some X in C
Question 3 True / False

The Stone-Čech compactification βX is the reflection of a topological space X into the subcategory of compact Hausdorff spaces, meaning every continuous map from X to any compact Hausdorff space factors uniquely through the canonical map X → βX.

TTrue
FFalse
Question 4 True / False

Nearly every full subcategory of a category is reflective, as long as it is closed under isomorphisms.

TTrue
FFalse
Question 5 Short Answer

What does it mean for a subcategory D to be reflective in C, and why is the universal property of the unit map η_X: X → L(X) the central fact — rather than merely the existence of a functor L: C → D?

Think about your answer, then reveal below.