Questions: Russell's Paradox

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A student argues: 'Russell's paradox just shows sets can't contain themselves. If we add an axiom that no set is a member of itself, the paradox is resolved.' What is wrong with this response?

AIt is correct — forbidding self-membership is exactly how ZFC resolves the paradox
BThe anti-self-membership rule would make R = {x : x ∉ x} the universal set of all sets, and forming it still requires unrestricted comprehension, which leads to other paradoxes
CThe response fails because self-membership is required by the axiom of extensionality
DForbidding self-membership would make all mathematical induction impossible
Question 2 Multiple Choice

Which of the following best describes what Russell's paradox actually establishes?

AIt shows that self-referential definitions are always meaningless and should be excluded from mathematics
BIt is a formal proof that naive set theory's axiom of unrestricted comprehension is inconsistent — any system containing it can prove every statement
CIt shows that infinite sets create contradictions, motivating a finitist approach to mathematics
DIt proves that the membership relation ∈ cannot be well-defined for all sets
Question 3 True / False

Zermelo's axiom of separation resolves Russell's paradox by allowing sets to be formed only as subsets of already-existing sets, so that no predicate can range over all sets simultaneously.

TTrue
FFalse
Question 4 True / False

Russell's type theory and Zermelo's axiom of separation are equally prominent as foundations for contemporary mathematics, and mathematicians today use both interchangeably.

TTrue
FFalse
Question 5 Short Answer

Explain in your own words why unrestricted comprehension — 'for any predicate P, there exists a set {x : P(x)}' — leads to a contradiction. What specific feature makes it dangerous?

Think about your answer, then reveal below.