Questions: Schrödinger Equation for Molecular Systems

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A student claims to have 'measured the molecular wavefunction ψ directly' in their spectroscopy experiment. What is fundamentally wrong with this claim?

ANothing — ψ can be measured directly by X-ray diffraction
BThe wavefunction ψ is not directly observable; only |ψ|² (the probability density) corresponds to measurable quantities
COnly ground-state wavefunctions can be measured; excited states are always inaccessible
DWavefunctions can be directly measured for atoms but the math becomes intractable for molecules
Question 2 Multiple Choice

The Born-Oppenheimer approximation makes the molecular Schrödinger equation tractable. What physical insight does it exploit?

ANuclear kinetic energy is negligible compared to electron kinetic energy, so nuclei can be ignored entirely
BElectron-electron repulsion and nuclear-nuclear repulsion cancel each other out at equilibrium
CNuclei are thousands of times more massive than electrons, so electrons adjust almost instantaneously to any nuclear arrangement — allowing nuclear positions to be treated as fixed parameters
DMolecules can be decomposed into non-interacting atom-sized subunits that each solve independently
Question 3 True / False

In the Born-Oppenheimer approximation, nuclear coordinates are treated as variables in the electronic Schrödinger equation.

TTrue
FFalse
Question 4 True / False

The potential energy surface obtained from the Born-Oppenheimer approximation has minima corresponding to stable molecular geometries and saddle points corresponding to transition states.

TTrue
FFalse
Question 5 Short Answer

Why can't the molecular Schrödinger equation be solved exactly for any system beyond H₂⁺, and what strategy does the Born-Oppenheimer approximation use to make it tractable?

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