The series Σ (1/n) — the harmonic series — has terms that approach zero as n → ∞. Does it converge?
AYes — since the terms go to zero, the partial sums must stabilize
BNo — the terms go to zero too slowly for the partial sums to converge
CYes — any series whose terms shrink to zero converges by definition
DIt depends on where you start the sum
The harmonic series diverges even though its terms approach zero. Terms going to zero is necessary but not sufficient for convergence. The partial sums of Σ(1/n) grow without bound — they just grow very slowly (logarithmically). This is the key asymmetry: if terms don't go to zero, the series definitely diverges, but the converse is false. The harmonic series is the canonical counterexample every calculus student must internalize.
Question 2 Multiple Choice
For the series Σ aₙ, the notation S_N refers to:
AThe Nth term of the series, aₙ evaluated at n = N
BThe sum of the first N terms: a₁ + a₂ + ⋯ + aₙ
CThe limit of the series as it approaches its sum S
DThe number of terms needed for the partial sum to exceed N
S_N is the Nth partial sum — a finite sum of the first N terms. This is a concrete, computable number. The series itself is defined as lim(N→∞) S_N. The confusion between aₙ (individual terms) and S_N (accumulated total) is one of the most common errors in this topic: aₙ is what you're adding; S_N is what you've added so far.
Question 3 True / False
Saying that an infinite series 'converges to S' is really a statement about a sequence of partial sums converging to S.
TTrue
FFalse
Answer: True
This is exactly the definition. The series Σ aₙ converges to S means the sequence {S_N} — where S_N = a₁ + ⋯ + aₙ — converges to S as N → ∞. This is not just a reformulation; it is the precise definition that makes infinite sums mathematically rigorous by reducing them to limits of sequences, which you already know how to handle.
Question 4 True / False
If the terms of a series approach zero, the series should converge.
TTrue
FFalse
Answer: False
This is the most persistent misconception in infinite series. The harmonic series Σ 1/n is the canonical counterexample: each term 1/n → 0, but the partial sums grow without bound. Terms approaching zero is a necessary condition for convergence — if terms don't go to zero, the series definitely diverges — but it is not sufficient. The terms must shrink fast enough that their cumulative sum stays bounded.
Question 5 Short Answer
Why can't we define an infinite series simply as 'the result of adding infinitely many numbers together,' the way we add finitely many numbers?
Think about your answer, then reveal below.
Model answer: Addition is a binary operation — it takes two inputs. Finite sums extend this by repeating the operation, but 'infinitely many additions' cannot be completed in any finite number of steps; there is no last step that yields a result. The definition via partial sums resolves this by converting the infinite process into a limit of finite computations: S_N = a₁ + ⋯ + aₙ is always well-defined, and we define the series as lim S_N.
Without this definition, 'infinite sum' is meaningless. The brilliance of the partial sums definition is that it reduces a new concept (infinite series) to a concept already understood (limits of sequences), giving access to all the tools of sequence analysis. Every convergence test you will learn is ultimately a test for whether the sequence {S_N} converges.