Questions: Sigma-Algebras and Measurable Sets

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Why does the definition of a sigma-algebra require closure under countable unions rather than under all possible (uncountably infinite) unions?

ACountable unions are computationally tractable while uncountable unions are not, making sigma-algebras more practical
BUncountably infinite unions can generate non-measurable sets — like Vitali sets — that cannot be assigned a consistent probability, leading to contradictions
CThe axiom of choice is only invoked for uncountable unions, which is philosophically unacceptable in standard probability theory
DProbability measures are only defined on finite or countably infinite sample spaces, making uncountable closure unnecessary
Question 2 Multiple Choice

Which of the following collections is a valid sigma-algebra on Ω = {a, b, c}?

A{∅, {a}, {b}, {c}} — contains all singletons and the empty set
B{∅, {a}, {b, c}, Ω} — the empty set, one singleton, its complement, and the full set
C{∅, {a, b}, {b, c}, Ω} — contains four sets including two overlapping pairs
D{{a}, {b}, {c}, Ω} — all singletons and the full set but not the empty set
Question 3 True / False

The trivial sigma-algebra {∅, Ω} satisfies all three formal requirements of a sigma-algebra, even though it only permits two events to be assigned probabilities.

TTrue
FFalse
Question 4 True / False

For probability on the real line, the standard practice is to use the power set of most subsets of ℝ as the sigma-algebra, since it is the largest possible collection.

TTrue
FFalse
Question 5 Short Answer

What problem do non-measurable sets like Vitali sets create for probability theory, and how does restricting attention to a sigma-algebra resolve the problem?

Think about your answer, then reveal below.