Questions: Sigma-Algebras and Measurable Sets

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

You want to assign a probability P to the event 'a randomly chosen real number lies in the Cantor set.' Why does this require the Cantor set to be in the sigma-algebra, and why can't we just assign probabilities to every subset of ℝ?

AWe can assign probabilities to every subset of ℝ — sigma-algebras are just a convention for organizing calculations
BThe sigma-algebra is needed only for uncountable sample spaces; for finite or countable spaces, every subset can receive a probability
CProbability must satisfy countable additivity: P(∪ Aₙ) = ΣP(Aₙ) for disjoint events. This forces the collection of 'events' to be closed under countable unions. Non-measurable sets exist for which no consistent probability assignment satisfies this requirement
DSigma-algebras restrict which sets receive probability to make computation tractable, but every subset of ℝ technically has a probability
Question 2 Multiple Choice

Which of the following collections of subsets of Ω = {1, 2, 3, 4} is NOT a valid sigma-algebra?

A{∅, {1,2}, {3,4}, {1,2,3,4}}
B{∅, {1}, {2,3,4}, {1,2,3,4}}
C{∅, {1,2}, {2,3}, {1,2,3,4}}
D{∅, {1,2,3,4}}
Question 3 True / False

A sigma-algebra that is closed under finite unions but not necessarily countable unions is sufficient for most of probability theory.

TTrue
FFalse
Question 4 True / False

A coarser sigma-algebra (one containing fewer measurable sets) represents less information about outcomes in a probability space.

TTrue
FFalse
Question 5 Short Answer

Why must a sigma-algebra be closed under *countable* unions specifically, rather than just finite unions? What goes wrong if we only require finite closure?

Think about your answer, then reveal below.