Questions: Spin Glasses and Quenched Disorder

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A physicist argues that a spin glass, like a paramagnet, shows no net magnetization, so it must be a special case of the paramagnetic phase. What is wrong with this argument?

ASpin glasses do have net magnetization — the Edwards-Anderson parameter is a form of long-range order
BThe physicist is correct: any magnetic system without long-range order is by definition paramagnetic
CAlthough the disorder-averaged magnetization is zero, individual spins in a spin glass freeze into fixed orientations, making the system non-ergodic and producing aging, memory effects, and history-dependence that a paramagnet never exhibits
DSpin glasses are actually frozen ferromagnets — their net magnetization is non-zero when measured in the right reference frame
Question 2 Multiple Choice

What is the crucial distinction between quenched and annealed disorder, and why does this distinction determine whether a spin glass phase can form?

AQuenched disorder means strong random couplings; annealed disorder means weak ones
BAnnealed disorder creates frustration; quenched disorder creates long-range ferromagnetic order
CThe distinction is thermodynamic: quenched systems are at low temperature, annealed systems are at high temperature
DQuenched disorder is frozen — random couplings are locked in by the material's structure and do not equilibrate with temperature. Annealed disorder thermalizes and averages out. Frozen couplings create static frustration and a rugged energy landscape; if they could equilibrate, the system would not get trapped in local minima
Question 3 True / False

A spin glass is essentially a frozen ferromagnet: like a ferromagnet cooled below its Curie temperature, it settles into a single preferred low-energy configuration with frozen spins.

TTrue
FFalse
Question 4 True / False

Frustration in a spin glass arises because frozen random couplings (some ferromagnetic, some antiferromagnetic) make it impossible for any single spin configuration to simultaneously satisfy all interactions, leading to many nearly degenerate local minima.

TTrue
FFalse
Question 5 Short Answer

Explain why a spin glass cannot be described as simply a paramagnet or ferromagnet, using the concept of the Edwards-Anderson order parameter.

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