Why is the absorption property of an ideal — that ra ∈ I and ar ∈ I for all r ∈ R — exactly the right condition to make the quotient R/I a well-defined ring, and why does the weaker closure condition of a subring fall short?
Think about your answer, then reveal below.
Model answer: The absorption property guarantees that coset multiplication is independent of which representative you choose. If a ∈ I and r ∈ R, then (r + a)s = rs + as, and as ∈ I (by absorption), so rs + as lands in the same coset as rs. Without absorption, choosing a different representative of a coset (by adding an element of I) could shift the product to a different coset, making multiplication ill-defined. A subring S is only closed under multiplication of two elements already in S; it says nothing about r·a when r ∉ S. This means the coset product (r + S)(s + S) = rs + S can be ambiguous, because adding an element of S to r before multiplying by s produces rs + (element of S)·s, and that element of S times s need not stay in S.
The algebraic moral: quotient constructions always require the substructure to 'absorb' the action of the ambient structure. In groups, normal subgroups absorb conjugation (gNg⁻¹ ⊆ N), enabling well-defined quotient group multiplication. In rings, ideals absorb multiplication from outside (rI ⊆ I), enabling well-defined quotient ring multiplication. The ring analogy of 'normal subgroup' is precisely 'ideal' — not 'subring.'