Questions: Superconductivity: Phenomenology (Meissner, London Equations)
4 questions to test your understanding
Score: 0 / 4
Question 1 Multiple Choice
A perfect conductor (σ = ∞) and a superconductor both carry current with zero resistance. What experiment distinguishes them?
AMeasuring the critical temperature
BApply a magnetic field above T_c, then cool below T_c. A perfect conductor would trap the field inside (dB/dt = 0 prevents change), while a superconductor actively expels the field (Meissner effect: B = 0 regardless of history). The field expulsion on cooling is the unique signature of superconductivity
CMeasuring the current-carrying capacity
DA perfect conductor has zero resistance only at T = 0
This is the crucial conceptual point. A perfect conductor (hypothetical material with σ → ∞) obeys Faraday's law: dB/dt = 0 inside, so whatever field was present when resistance vanished would be frozen in. A superconductor actively expels field (B → 0) regardless of whether the field was applied before or after cooling through T_c. This means superconductivity is an equilibrium thermodynamic phase with B = 0 as a state variable, not merely a kinetic property (zero resistance). The Meissner effect requires the London equation curl(J) ∝ -B, not just E = ρJ with ρ = 0.
Question 2 Multiple Choice
The London penetration depth λ_L sets the length scale over which magnetic fields decay inside a superconductor. What determines its magnitude?
AThe crystal lattice spacing
Bλ_L = √(mc²/4πn_se²) depends on the superfluid density n_s — higher n_s means more screening current available and shorter penetration depth. Typical values are 20-200 nm, much larger than atomic spacings but much smaller than macroscopic samples
CThe mean free path of electrons
DThe Debye temperature of the material
The London penetration depth is set by the inertia of the superconducting electrons (mass m) versus their ability to screen (charge e and density n_s). Near T_c, n_s → 0 and λ_L → ∞ (the superconductor can no longer screen fields effectively). At T = 0, λ_L has its minimum value, typically 20-50 nm for elemental superconductors. The temperature dependence λ(T)/λ(0) ≈ [1 - (T/T_c)⁴]^{-1/2} (approximately) provides experimental access to the superfluid density.
Question 3 True / False
The Meissner effect (B = 0 inside a superconductor) proves that superconductivity is a thermodynamic equilibrium state, not merely a kinetic phenomenon (zero resistance).
TTrue
FFalse
Answer: True
If superconductivity were only zero resistance (perfect conduction), the internal magnetic field would depend on the history — field applied before or after the transition. The Meissner effect shows that B = 0 inside regardless of history: the superconducting state is uniquely defined by (T, H), just like an equilibrium thermodynamic phase. This allows treatment by thermodynamics: the free energy difference between normal and superconducting states determines the critical field H_c via the condensation energy H_c²/8π. Without the Meissner effect, there would be no thermodynamic framework for superconductivity.
Question 4 Short Answer
Derive the London penetration depth from the London equation and explain what happens physically at the surface of a superconductor in an applied field.
Think about your answer, then reveal below.
Model answer: Starting from the London equation curl(J_s) = -(n_se²/mc)B and Ampere's law curl(B) = (4π/c)J_s, taking the curl of Ampere's law and substituting gives ∇²B = B/λ_L², with λ_L = √(mc²/4πn_se²). For a flat surface with field B₀ applied parallel, the solution is B(x) = B₀ exp(-x/λ_L). Physically, the applied field induces persistent screening currents in a surface layer of thickness ~λ_L. These currents produce a field that exactly cancels the applied field in the interior. The screening currents flow without resistance (supercurrent) and create the perfect diamagnetic response. The superconductor pays a kinetic energy cost (½mv²n_s per unit volume in the screening layer) to maintain these currents.
The exponential decay of the field — not abrupt cancellation — is key. The penetration depth is measurable by muon spin rotation, microwave surface impedance, or the magnetic field dependence of the London moment in rotating superconductors.