Questions: Synonymous vs. Non-synonymous Substitutions
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
You compare a gene encoding a core histone protein between humans and yeast and find dN/dS = 0.005. You compare a gene encoding a reproductive protein and find dN/dS = 1.8. What do these values indicate about the selective pressures on each protein?
AThe histone gene mutates 360 times more slowly than the reproductive gene because histones are better protected by DNA repair
BThe histone gene is under intense purifying selection (nearly all amino acid changes are deleterious), while the reproductive gene is under positive selection favoring amino acid change
CThe histone gene has fewer nonsynonymous sites, making dN/dS artificially low
DBoth genes are evolving neutrally, but the histone gene has a much lower mutation rate
dN/dS reflects selection, not mutation rate — synonymous changes serve as the internal control for the neutral mutation rate in the same gene. A dN/dS of 0.005 for histones means 99.5% of amino acid changes are removed by purifying selection (histones are so constrained that they are nearly identical across all eukaryotes). A dN/dS of 1.8 means nonsynonymous changes are accumulating faster than synonymous ones — impossible under neutrality, and only explainable by selection actively *favoring* protein evolution, as occurs in immune and reproductive arms races. Option D is wrong because the synonymous rate is the baseline — if mutation rate differed, both dN and dS would change proportionally.
Question 2 Multiple Choice
A synonymous substitution changes a codon from CUU to CUC. Why is this substitution expected to accumulate at approximately the neutral mutation rate?
ASynonymous substitutions are in non-coding regions and are not visible to repair machinery
BBoth codons encode leucine, so the amino acid sequence is unchanged; the protein's function is unaffected, leaving natural selection no foothold to remove or favor the change
CSynonymous changes occur at the third codon position, which mutates faster due to polymerase slippage
DNatural selection cannot detect changes smaller than a full codon
The key is that synonymous substitutions leave the protein sequence unchanged — and protein function is what selection primarily acts on. A change that does not alter the protein provides no fitness difference, so selection neither removes it (no purifying selection) nor promotes it (no positive selection). These changes are effectively neutral and accumulate at the rate determined by the background mutation rate. Option C contains a kernel of truth (wobble position mutates more readily) but that is not the reason synonymous changes are neutral — they accumulate neutrally because they have no protein-level consequence.
Question 3 True / False
A gene showing dN/dS ≈ 1 across its entire length is likely evolving under positive selection that is balanced against purifying selection.
TTrue
FFalse
Answer: False
dN/dS ≈ 1 is the signature of *neutral evolution*, not a balance between positive and purifying selection. It means nonsynonymous and synonymous changes are accumulating at the same rate, implying that amino acid changes in this protein have little or no fitness effect — the protein is not strongly constrained but is also not under directional pressure. Balanced positive and purifying selection would produce different dN/dS values at different sites or lineages, not a genome-wide average near 1. Pure neutrality (no selection at all) is the most parsimonious interpretation of dN/dS = 1.
Question 4 True / False
A synonymous substitution can, in principle, affect an organism's fitness even though it does not change the encoded amino acid.
TTrue
FFalse
Answer: True
Synonymous substitutions are treated as *approximately* neutral in the dN/dS framework, but they are not always perfectly neutral. Synonymous changes can affect codon usage bias (some codons are translated faster or more accurately, affecting protein production speed), mRNA secondary structure (which influences stability and translation), exonic splicing enhancers (regulatory sequences that overlap with coding sequence), and in some cases protein folding speed (cotranslational folding can depend on translation pauses at rare codons). The dN/dS method uses synonymous rate as an approximation of the neutral mutation rate, and for most genes this is reasonable — but it is an approximation.
Question 5 Short Answer
Explain why dN/dS > 1 can only arise from positive (diversifying) selection, and cannot simply reflect a higher neutral mutation rate at nonsynonymous sites.
Think about your answer, then reveal below.
Model answer: The dN/dS ratio is designed to control for mutation rate differences. Both dN and dS are calculated from the same gene, exposed to the same mutation rate — synonymous changes serve as the internal control. If mutation rate were elevated at nonsynonymous sites specifically, it would elevate dS at those positions too (since third-codon synonymous sites and second-codon nonsynonymous sites share the same gene context). The only way dN can exceed dS is if natural selection is *removing* synonymous changes (making dS artificially low) — which makes no sense, since synonymous changes are neutral — or if selection is *favoring* nonsynonymous changes and increasing their fixation rate above the neutral expectation. The latter is positive selection by definition.
In other words, because synonymous changes are used as the neutral rate benchmark *within the same gene*, the ratio is self-normalizing with respect to mutation rate. dN/dS > 1 is a clear signal that cannot be explained by mutation alone — it requires that natural selection is driving amino acid divergence at a rate exceeding what neutral drift would produce.