Questions: The Standard Matrix of a Linear Transformation
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
A student wants to find the standard matrix for T: ℝ² → ℝ² defined by T(x, y) = (2x + y, x − 3y). What is the correct procedure?
ACompute T(1, 0) = (2, 1) and T(0, 1) = (1, −3); assemble these as the columns of A
BSolve the system Ax = T(x) for A using row reduction on sample inputs
CFind vectors that A maps to e₁ and e₂ and use those as rows
DAverage T's output over many random inputs to estimate A's entries
The standard matrix is assembled directly from the images of the basis vectors as columns — no equation solving required. T(e₁) = T(1, 0) = (2, 1) becomes column 1; T(e₂) = T(0, 1) = (1, −3) becomes column 2. This works because linearity guarantees T(x) = x₁·T(e₁) + x₂·T(e₂), which is exactly what Ax computes.
Question 2 Multiple Choice
The standard matrix of a 90° counterclockwise rotation is [[0, −1], [1, 0]]. Why is the first column [0, 1]ᵀ rather than [1, 0]ᵀ?
ABecause e₁ = [1, 0]ᵀ maps to [0, 1]ᵀ under a 90° counterclockwise rotation, and columns encode where basis vectors go
BBecause [1, 0]ᵀ is reserved for identity matrices and cannot appear as a rotation column
CBecause columns of a rotation matrix must always be perpendicular to the rows
DBecause rows encode where basis vectors go; the first row therefore cannot match e₁
Column j of the standard matrix is T(eⱼ). Rotating e₁ = [1, 0]ᵀ by 90° counterclockwise produces [0, 1]ᵀ — that becomes column 1. Rotating e₂ = [0, 1]ᵀ produces [−1, 0]ᵀ — that becomes column 2. The common mistake in option D (rows encode basis images) would produce the transpose, which represents a different transformation.
Question 3 True / False
The standard matrix of a linear transformation is independent of what basis you use for the input and output spaces.
TTrue
FFalse
Answer: False
The 'standard' qualifier specifically means the standard basis is used for both domain and codomain — that's what makes it standard. Use a different basis and the same transformation T has a different matrix representation. The study of change of basis is precisely about converting between these representations. Basis-independence would mean every transformation has only one matrix, which is false.
Question 4 True / False
To construct the standard matrix of T: ℝⁿ → ℝᵐ, you should evaluate T on most vector in ℝⁿ.
TTrue
FFalse
Answer: False
You only need T evaluated on the n standard basis vectors e₁, …, eₙ. By linearity, any vector x = x₁e₁ + ··· + xₙeₙ gives T(x) = x₁T(e₁) + ··· + xₙT(eₙ), which the matrix product Ax reproduces automatically. The entire transformation on an infinite domain is encoded in just n basis images — this is the power of linearity.
Question 5 Short Answer
Why is it sufficient to know T(e₁), T(e₂), …, T(eₙ) to completely determine a linear transformation T: ℝⁿ → ℝᵐ?
Think about your answer, then reveal below.
Model answer: Any vector x ∈ ℝⁿ decomposes as x = x₁e₁ + ··· + xₙeₙ. Linearity then gives T(x) = x₁T(e₁) + ··· + xₙT(eₙ). Knowing T on the basis vectors determines T on every linear combination of them — which is every vector in ℝⁿ.
This is the fundamental theorem behind the standard matrix. A linear transformation is completely and uniquely determined by its values on a basis, because linearity 'extends' those values to all of ℝⁿ without ambiguity. The matrix is just the data structure that packages the n basis images so that Ax replicates the extension automatically.