Questions: Variational Method for Ground State Approximation

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A student computes the energy of trial wave function ψ_A and gets −13.2 eV. A second student uses a different trial function ψ_B and gets −13.8 eV. The true ground state energy is −13.6 eV. What can you conclude?

Aψ_B violates the variational principle because its energy is below the true ground state
Bψ_A is the better approximation because it is closer to zero
Cψ_B is the better approximation because it gives a lower energy, even though it is below the true value
DNeither result is valid; both should be recomputed with larger basis sets
Question 2 Multiple Choice

A researcher adds a second adjustable parameter to a trial wave function and re-minimizes the energy. How does this affect the result?

AIt may raise or lower the energy — adding parameters makes the result less predictable
BIt will leave the energy unchanged, since one parameter is already sufficient
CIt can only lower (or maintain) the energy, since a more flexible function can always do at least as well
DIt will raise the energy, because more parameters introduce additional approximation error
Question 3 True / False

The variational principle guarantees that optimizing a trial wave function will eventually yield the exact ground state energy if enough parameters are added.

TTrue
FFalse
Question 4 True / False

The variational method can determine the exact energy of excited states just as reliably as it determines the ground state energy.

TTrue
FFalse
Question 5 Short Answer

Why does the variational principle transform the quantum mechanical problem from an unsolvable differential equation into an optimization problem, and why is this useful?

Think about your answer, then reveal below.