Questions: The Variational Principle in Quantum Mechanics

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A physicist uses a trial wavefunction to estimate the ground state energy of helium and obtains E_trial = −77.5 eV. The true ground state energy is E₀ = −79.0 eV. What does the variational principle say about this result?

AThe result is invalid because it differs from the true answer by more than 1%.
BE_trial > E₀, which is consistent with the variational principle — the trial wavefunction gives an upper bound, not the exact answer.
CThe variational principle has been violated because the true energy is lower than the computed value.
DThe trial wavefunction is close enough that further optimization is unnecessary.
Question 2 Multiple Choice

Why is the variational method particularly powerful for many-electron systems like molecules, where exact solutions are impossible?

AIt provides exact analytic solutions to the Schrödinger equation for any system with more than two electrons.
BIt replaces the eigenvalue problem (finding E₀ exactly, which is often intractable) with an optimization problem that can be systematically improved by enriching the trial wavefunction family.
CIt works only for ground states and is not applicable to excited states or molecular systems.
DIt requires knowing the true ground state energy E₀ first, using it as a reference for the optimization.
Question 3 True / False

For any normalized quantum state |ψ⟩ that is not the true ground state, the expectation value ⟨ψ|Ĥ|ψ⟩ is strictly greater than the ground state energy E₀.

TTrue
FFalse
Question 4 True / False

A variational calculation that produces a lower energy than a previous trial wavefunction has necessarily found a better approximation to the ground state.

TTrue
FFalse
Question 5 Short Answer

Why does the variational principle guarantee an upper bound — rather than a lower bound — on the ground state energy?

Think about your answer, then reveal below.