Questions: Simple Harmonic Motion and Natural Frequency

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A spring-mass system is oscillating with amplitude A. If you increase the initial displacement to 2A without changing the spring or mass, what happens to the natural frequency?

AIt doubles — the system now oscillates with twice the energy, so it moves faster
BIt increases by a factor of √2 — energy is proportional to A², so frequency scales accordingly
CIt decreases — the larger displacement means the mass takes more time to travel the full cycle
DIt remains unchanged — natural frequency depends only on k and m, not on amplitude
Question 2 Multiple Choice

An engineer uses the energy method to find the natural frequency of a compound pendulum. She writes E = ½Iθ̇² + ½k_eff θ², differentiates with respect to time, and sets dE/dt = 0. What equation does she arrive at?

AIθ̈ + k_eff θ = 0, revealing ω_n = √(k_eff/I)
BIθ̈ = k_eff θ, which requires numerical solution for ω_n
Cθ̈ = 0, indicating no oscillation occurs
DdE/dt = 0 only holds at equilibrium and gives no information about frequency
Question 3 True / False

The natural frequency of a spring-mass system is independent of the amplitude of oscillation.

TTrue
FFalse
Question 4 True / False

Attaching a heavier mass to a spring increases the natural frequency because more mass stores more kinetic energy and therefore oscillates faster.

TTrue
FFalse
Question 5 Short Answer

Explain why the energy method (setting dE/dt = 0 for a conservative system) yields the natural frequency, and why it is sometimes preferred over Newton's second law for this purpose.

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