According to the von Neumann construction, what is the ordinal 3?
A{1, 2, 3}
B{0, 1, 2}
C{{∅}}
DThe set containing only ∅
In the von Neumann representation, each ordinal equals the set of all smaller ordinals. So 3 = {0, 1, 2}. It is not {1,2,3} — ordinals begin at 0 = ∅. The ordinal n always has exactly n elements, confirming the size-equals-value property.
Question 2 True / False
Ordinal addition is commutative: for any ordinals α and β, α + β = β + α.
TTrue
FFalse
Answer: False
Ordinal arithmetic is not commutative. The standard counterexample: 1 + ω = ω, because appending one element before the sequence 0,1,2,... still yields an ω-sequence. But ω + 1 > ω, because appending one element after the ω-sequence creates a new limit with a successor at the end. Order of concatenation changes the order type.
Question 3 Short Answer
What does it mean for a set α to be transitive, and why is transitivity part of the definition of a von Neumann ordinal?
Think about your answer, then reveal below.
Model answer: A set α is transitive if every element of α is also a subset of α (x ∈ α implies x ⊆ α). Transitivity ensures each ordinal is closed downward — it contains all elements of its elements — making ordinals canonical, self-contained representations of all smaller ordinals.
Without transitivity, two well-ordered sets with the same order type could look different internally. Transitivity, combined with well-ordering by ∈, forces a unique canonical form: the ordinal α is exactly the set of all ordinals less than α, with no extraneous elements.