Questions: Wagner's Theorem

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Graph G contains K₅ as a minor but does NOT contain any subdivision of K₅ or K₃,₃. By Wagner's theorem, is G planar?

AYes — G contains no subdivision of K₅ or K₃,₃, so Kuratowski's condition is satisfied and G must be planar.
BNo — Wagner's theorem shows that containing K₅ as a minor is sufficient to conclude non-planarity, and this condition is equivalent to Kuratowski's.
CWe cannot determine planarity without checking Kuratowski's condition separately from Wagner's.
DOnly K₃,₃ as a minor is relevant to planarity; K₅ minors alone do not determine it.
Question 2 Multiple Choice

Why is 'containing H as a minor' a weaker condition than 'containing a subdivision of H'?

AMinors can only be formed by edge contraction, making them harder to find than subdivisions.
BA graph that contains a subdivision of H automatically contains H as a minor (by contracting the inserted degree-2 vertices), but not every minor arises from a subdivision.
CSubdivisions insert vertices that always increase the minor count of a graph.
DMinors require the graph to have more vertices, while subdivisions only require more edges.
Question 3 True / False

Wagner's theorem and Kuratowski's theorem give equivalent characterizations of planarity, even though graph minors and subdivisions are different structural relationships.

TTrue
FFalse
Question 4 True / False

Since 'containing H as a minor' is weaker than 'containing a subdivision of H,' Wagner's theorem forbids a strictly larger class of graphs than Kuratowski's theorem.

TTrue
FFalse
Question 5 Short Answer

Why does Wagner's theorem matter beyond being an alternative restatement of Kuratowski's theorem?

Think about your answer, then reveal below.