Questions: EIGRP: Enhanced Interior Gateway Routing Protocol

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Router A currently reaches destination X via neighbor B with a feasible distance (FD) of 100. Neighbor B reports an advertised distance (AD) of 70. Neighbor C reports an AD of 110. Which neighbor can serve as a feasible successor (loop-free backup)?

AOnly C — it has a higher AD, meaning it has a longer path that could not be routing back through A
BOnly B — its AD (70) is strictly less than the current FD (100), satisfying the feasibility condition and guaranteeing a loop-free alternate path
CBoth B and C — any alternate path qualifies as a feasible successor
DNeither — a feasible successor can only be selected after B's route fails and DUAL queries are sent
Question 2 Multiple Choice

A network engineer needs to minimize routing protocol bandwidth overhead on a WAN link. Why would she prefer EIGRP over RIP?

AEIGRP uses a simpler hop-count metric that requires less computation to advertise
BEIGRP sends only incremental, triggered updates when topology changes occur — not periodic full routing-table broadcasts like RIP's 30-second updates
CEIGRP compresses its routing table before transmission, reducing packet size
DEIGRP automatically reduces update frequency when bandwidth is congested
Question 3 True / False

EIGRP's feasibility condition guarantees that a feasible successor cannot be routing traffic back through the querying router, making loop-free instant failover possible.

TTrue
FFalse
Question 4 True / False

In EIGRP, the feasible distance (FD) for a route and the advertised distance (AD) reported by the successor router refer to the same metric value.

TTrue
FFalse
Question 5 Short Answer

Explain how EIGRP's feasibility condition prevents routing loops during a topology change, and contrast this with how RIP handles the same situation.

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