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The finite square well is a region of constant negative potential, V = −V₀ for |x| < a, with V = 0 outside. Bound states have energies between −V₀ and 0; their wavefunctions oscillate inside the well and decay exponentially outside, so the particle has a nonzero chance of being found in the classically forbidden region. Matching ψ and dψ/dx at the walls gives transcendental equations. Their graphical solution shows that the well holds only a finite number of bound states, and in one dimension it always holds at least one. States with E > 0 are scattering states, which pass over the well and are partly reflected.
Solve inside and outside separately, then impose continuity of ψ and ψ' at x = a. Use the even/odd symmetry to split the problem in two. Solve the resulting equations graphically by plotting tan z against √(z₀²/z² − 1), which shows at a glance how many states exist. Compare the results with the infinite well of the same width in both the deep and shallow limits.
The infinite square well is a useful first model, but real potentials have finite depth. Take V = −V₀ inside |x| < a and V = 0 outside, and look first for bound states with −V₀ < E < 0.
Inside the well the kinetic energy E + V₀ is positive, so the Schrödinger equation gives oscillating solutions with wavenumber k = √(2m(E + V₀))/ħ. Outside, the energy is below the potential, and the solutions are real exponentials, e−κ|x|, with κ = √(−2mE)/ħ. Only the decaying exponential is allowed, because a growing one cannot be normalized. The particle has a real chance of being found outside the well, in a region where classical physics says it could never go.
The potential is symmetric, so the solutions can be chosen even or odd. For even states, ψ = cos kx inside. Requiring both ψ and dψ/dx to be continuous at x = a gives κ = k tan(ka). For odd states, ψ = sin kx inside, and the condition becomes κ = −k cot(ka). These equations cannot be solved in closed form. Introduce z = ka and z₀ = (a/ħ)√(2mV₀). The even condition becomes tan z = √(z₀²/z² − 1). Plotting both sides shows the solutions as crossing points. The right side falls to zero at z = z₀, so only a finite number of crossings exist.
Several results follow from the graph. There is always at least one even state, since the first branch of tan z starts at zero and rises without limit before z = π/2. A new bound state, alternately odd and even, appears each time z₀ passes a multiple of π/2. For a deep, wide well (large z₀), the low-lying levels approach those of an infinite well of width 2a, measured from the bottom. For any finite depth they lie a little lower, because the wavefunction leaks into the walls.
For E > 0 the particle is not bound. It travels over the well and is partly reflected at the edges. The transmission coefficient reaches exactly 1 when the well's width holds a whole number of half-wavelengths, a condition 2a√(2m(E + V₀))/ħ = nπ. This perfect transmission is related to the Ramsauer-Townsend effect, in which slow electrons pass through noble-gas atoms almost without scattering. The finite well also serves as a first model for electrons in quantum-well semiconductor devices and for nucleons in a nucleus.