An ideal gas undergoes isothermal expansion (temperature stays constant). Which statement correctly describes what happens?
AThe gas does no work because its temperature does not change
BNo heat flows because internal energy is a state function
CThe gas does positive work and an equal quantity of heat flows in
DBoth heat and work are zero since ΔU = 0
For an ideal gas, internal energy depends only on temperature. At constant T, ΔU = 0. From the First Law: ΔU = Q − W gives 0 = Q − W, so Q = W. The gas expands (positive work done by the gas, W > 0), and heat must flow in from the surroundings (Q > 0) to supply that energy. Options A and D incorrectly conclude work or heat are zero from ΔU = 0 — a direct target of the most common misconception.
Question 2 True / False
Heat and internal energy are essentially the same thing — heat is just the name for the energy stored inside a system.
TTrue
FFalse
Answer: False
Internal energy (U) is a state function — a property of the system's current thermodynamic state (temperature, pressure, volume). Heat (Q) is an energy transfer process, not a stored quantity. A system does not 'contain heat'; it contains internal energy. Heat describes energy crossing the boundary during a process. Conflating them is a foundational error: you can have Q = 0 with large ΔU (adiabatic work), or ΔU = 0 with large Q (isothermal expansion).
Question 3 Short Answer
A gas is compressed adiabatically (Q = 0). What happens to its internal energy, and why? Use the First Law explicitly.
Think about your answer, then reveal below.
Model answer: Internal energy increases. With Q = 0, the First Law gives ΔU = Q − W = 0 − W = −W. Compression means work is done ON the gas, so W < 0 by the system-centric sign convention (the system does negative work). Therefore ΔU = −W > 0: the internal energy — and thus the temperature — rises.
This is why a bicycle pump gets warm and why diesel engines ignite fuel by compression alone: adiabatic compression converts mechanical work entirely into internal energy. The sign convention is critical here — W is work done BY the system, so compression (work done ON the system) is W < 0.