Questions: Nyquist Criterion and Stability from Frequency Response

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A feedback system has an open-loop transfer function with 2 unstable poles (P = 2). The engineer plots the Nyquist diagram and counts 1 clockwise encirclement of the (-1, 0) point. What does this imply about the closed-loop system?

AThe closed-loop system is stable because only 1 encirclement is present
BThe closed-loop system is unstable: N = Z - P gives Z = N + P = 1 + 2 = 3 unstable closed-loop poles
CThe result is inconclusive — the Bode plot must also be checked before drawing conclusions
DThe closed-loop system is marginally stable since the Nyquist plot did not pass through (-1, 0)
Question 2 Multiple Choice

Why is the point (-1, 0) specifically the critical point in the Nyquist criterion, rather than the origin or any other reference?

AIt is chosen by convention to make the gain margin equal to 1 at marginal stability
BA closed-loop instability occurs when 1 + G(jω)H(jω) = 0, i.e., G(jω)H(jω) = -1, which is exactly the point (-1, 0) — the gain and phase condition for marginal closed-loop instability
CThe (-1, 0) point is where the phase of the open-loop transfer function crosses 0°, marking the natural frequency
D(-1, 0) is the point where the open-loop gain equals the phase margin by definition
Question 3 True / False

The Nyquist criterion can correctly determine closed-loop stability even when the open-loop transfer function has poles in the right half plane.

TTrue
FFalse
Question 4 True / False

Gain margin and phase margin derived from a Bode diagram provide an equivalent and equally reliable stability assessment to the Nyquist criterion, including for systems with open-loop unstable poles.

TTrue
FFalse
Question 5 Short Answer

Why does the Nyquist criterion analyze encirclements of (-1, 0) rather than simply checking whether the open-loop transfer function has any poles in the right half plane?

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