For a finite Galois extension K/F, there is a bijection between subgroups of Gal(K/F) and intermediate fields F ⊆ E ⊆ K. This bijection is order-reversing: larger subgroups correspond to smaller fields.
The Fundamental Theorem of Galois Theory is the crowning result of the Galois correspondence — it reveals a complete dictionary between algebra (subgroups of the Galois group) and the geometry of field extensions (intermediate fields). Since you have studied Galois groups, you know that Gal(K/F) is the group of field automorphisms of K that fix F pointwise. The theorem says this group encodes everything about the "landscape" of intermediate fields sitting between F and K.
The key word is bijection: every subgroup H of Gal(K/F) corresponds to exactly one intermediate field E = K^H (the fixed field of H), and every intermediate field corresponds to exactly one subgroup. Nothing is missed; nothing is duplicated. The fixed field K^H consists of all elements of K that every automorphism in H leaves unchanged. You can think of H as a "symmetry group" of K — the elements that H's symmetries cannot disturb form precisely the fixed field.
The order-reversing character is the most surprising feature. Bigger subgroup → smaller fixed field. Why? A larger subgroup has more automorphisms, and with more automorphisms imposing rigidity, fewer elements survive — so the fixed field shrinks. Conversely, a smaller subgroup has fewer constraints, allowing more elements to be fixed. Formally, |Gal(K/E)| = [K:E] and [E:F] = [Gal(K/F) : Gal(K/E)]. The field degrees and subgroup indices match exactly, quantifying the correspondence.
There is also a structural theorem for normal subgroups: H is normal in Gal(K/F) if and only if the fixed field E = K^H is itself a Galois extension of F. In that case, Gal(E/F) ≅ Gal(K/F)/H. Normal subgroups correspond to "nice" intermediate extensions — ones whose own Galois groups appear as quotients of the big Galois group. This is the algebraic link to the insolvability of the quintic: a polynomial is solvable by radicals if and only if its Galois group is solvable (has a chain of normal subgroups with abelian quotients), and the general quintic's Galois group S₅ is not solvable.